| There are two major variables in test box design:
1. One meter or three (and occasionally four)
2. Internal ohmmeter circuit or plugs to a purchased multimeter
What were you thinking about? We'll be better able to help you.
Higher voltage is not necessarily good. The basic equation is ohms law,
I=E/R. I= current in amps, E = Electro-motive force in volts, R=Resistance in ohms.
You want to measure, let's say, 5 ohms center scale. If you use 1.5v, this is:
I=1.5/5 = .3A = 300ma. That's a fairly large current, but not too bad.
Let's try it with 18V
I=18/5 = 3.6 A. That's huge. You don't want to do that.
The only way to use an 18v battery is to drop the voltage much lower. You could do that (a voltage divider for example).
The question above enters into this. If you want a 3 meter test box, you need three independent power sources. You could have 3 batteries, or you could do a DC to DC converter with 3 secondaries. The latter would fix the voltage problem too, because you could have an 18v primary and a 1V secondary. Well, 1V secondary regulation is hard, but you could do something reasonable. How much work do you want to get into, and how much do you know about designing DC to DC converters?
Of course the other question above enters into it too. If you use an external, purchased multimeter (with a 1X resistance scale), the battery is in the multimeter and is usually one or two AA or AAA cells. |